- #Php convert array to string how to
- #Php convert array to string update
- #Php convert array to string full
- #Php convert array to string registration
- #Php convert array to string code
The full syntax of an implode() looks like this: implode(" ", $array) NB: implode() doesn’t work with nested arrays. The array on the other hand could be an associative array or an indexed array. If you don’t pass in the separator, implode() still works. It is valid as long as you specify it in quotes. The separator could be any character or an empty string. Implode() takes in two values as parameters – the separator and the array you want to convert to a string. Once you pass in the array to implode(), it joins all the values to a string. It doesn’t matter whether the array is an indexed or associative array. implode() doesn’t modify the original array. Here each row is an object, where you have only a single parameter because in your query you asked for a single named option.In PHP, the implode() function is a built-in function that takes an array and converts it to a string. It's an array of objects! Objects are not strings. The problem here is that implode will take an array of strings, and join them together using a glue parameter, such as commas.īut by your own admission, $low_date is not an array of strings.
#Php convert array to string code
This code was all I needed to retrieve the key and pass it to a new variable to use in my SQL.
#Php convert array to string how to
Update: Tom helped me understand that I needed to pass the value of the array (which always returns as a single key array) to a new string, but I wasn't sure how to retrieve the value of an array key due to being a bit new to PHP. What am I missing? I'm a bit new to PHP so maybe I'm just missing something simple.
#Php convert array to string registration
Query works as expected in PHPmyAdmin when I hardcode the dates, and I can see the proper dates being returned when I print the variable, so I think my problem is that I need to convert the array to a string.īelow the initial registration of the $low_date, I attempt to implode it: $low_date_str = implode($low_date)
#Php convert array to string update
$user_id = $row->user_id //putting the user_id field value in variable to use it later in update query If(!empty($results)) // Checking if $results have some values or notĮcho "" // Adding and tag outside foreach loop so that it wont create again and againĮcho '' //This prevents duplicate rows for header records since it's above the loop WHERE user_id = $user_id AND vwd.next_pmt_dt BETWEEN '$low_date' AND '$high_date' ORDER BY next_pmt_dt ASC" ) // Query to fetch data from database table and storing in $results SELECT account_name, current_balance, minimum_due, last_pmt_amt, DATE_FORMAT((CONCAT(next_pmt_dt_yy, '-', next_pmt_dt_mm, '-', due_day)), '%Y-%m-%d') AS next_pmt_dt, autopay, status, account_type, url FROM accounts) vwd
I'm trying to use the $low_date and $high_date (not shown) in a query to look between date fields: get_results ( "SELECT * FROM ( When I print_r the $low_date, I get: Array ( => stdClass Object ( => ) ) The query returns the correct date that I need. PHP Code (I am returning a low date based off of a query that dynamically builds dates from a single date entered by a user): get_results("SELECT low_date FROM (SELECT low_date FROM (SELECT temp, (select * from (select adddate((SELECT main.date FROM (SELECT DATE_FORMAT((CONCAT(starting_deposit_dt_yy, '-', starting_deposit_dt_mm, '-', starting_deposit_dt_dd)), '%Y-%m-%d') AS `date` FROM income WHERE user_id = $user_id) AS main) ,t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) low_date from (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0, (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1, (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2, (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3, (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v where low_date between (SELECT DATE_FORMAT((CONCAT(starting_deposit_dt_yy, '-', starting_deposit_dt_mm, '-', starting_deposit_dt_dd)), '%Y-%m-%d') FROM income where user_id = $user_id) and DATE_ADD(DATE(SYSDATE()), INTERVAL 365 DAY)) d WHERE + 1) % 14 = 1 ORDER BY low_date ASC) s WHERE low_date low_date My understanding of implode was that it will convert the array variable into a string. I've tried imploding the string but I keep getting the error. However, I keep getting "Object of class stdClass could not be converted to string" error. I'm attempting to convert the SQL results of an array into a string so I can use the variables as BETWEEN date variables.
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